string.gsub使用中的疑惑

tianheng

string.gsub使用中的疑惑

1. 
   
2. function teststr()
   
3.         local str = "down,northeast,east,north ,south,southeast,out";
   
4.         print(string.gsub(str, "out", "", 1));
   
5. end
   

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输出为：down,northeast,east,north ,sh,southeast,out 1

期望是：down,northeast,east,north ,south,southeast, 1

怎么用，盼指点

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tianheng

自己写了个替换函数，无奈不熟悉正则

1. 
   
2. function teststr()
   
3.         local str = "down,northeast,east,north,south,southeast,out,up";
   
4.         print(str);
   
5.         print(string.find(str, "out"));
   
6.         print(string.gsub(str, "out", "", 1));
   
7.         
   
8.         print(delstr(str, ",", "out"));
   
9. end
   
10. 
    
11. function delstr(str, p, s)
    
12.         local t = utils.split(str, p)
    
13.         local r = {}
    
14.         for k, v in pairsByKeys(t) do
    
15.                 if v ~= s then
    
16.                         table.insert(r, v)
    
17.                 end
    
18.         end
    
19.         return table.concat(r, p)
    
20. end
    

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结果：
down,northeast,east,north,south,southeast,out,up 28 30
down,northeast,east,north,sh,southeast,out,up 1
down,northeast,east,north,south,southeast,up

emyt

1. function teststr()
   
2.         local str = "down,northeast,east,north ,south,southeast,out";
   
3.         print(string.gsub(str, ",out", "", 1));
   
4. end

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这样写不就行了

emyt

有时候换个思路就好，
还有str = "down,northeast,east,north ,south,southeast,out"
引号里是一个字符串 "," 逗号也是字符串的元素之一，gsub是针对整个字符串操作的当然出这样的结果

tianheng

out是第一个呢？

emyt

local str = "down,northeast,east,north ,south,southeast,out"
print(string.gsub(string.gsub(str,",out", "", 1),"out,", "", 1))

emyt

有思路照搬一次就行了啊